Math, asked by giya2566, 1 year ago

Show that there exit only one value 'c' for which the system cx+3y+(3-c)=0 ; 12x+cy-c=0, has infinitely many solutions. Find the value of 'c'.

Answers

Answered by ritikrathi9876

1

Answer: For infinity many solutions:

a1/a2=b1/b2=c1/c2

ATQ.

c/12=3/c=3-x/-c

cross multiplying

c²=36

c =6

Answer:6

Step-by-step explanation:

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