Show that there exit only one value 'c' for which the system cx+3y+(3-c)=0 ; 12x+cy-c=0, has infinitely many solutions. Find the value of 'c'.
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Answer: For infinity many solutions:
a1/a2=b1/b2=c1/c2
ATQ.
c/12=3/c=3-x/-c
cross multiplying
c²=36
c =6
Answer:6
Step-by-step explanation:
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