Physics, asked by sandeepperaka9467, 1 year ago

Show that there is a loss of kinetic energy and during perfectly inelastic collision

Answers

Answered by RahulRay123
3

An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.

Answered by BrainlyBAKA
1

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From conservation of momentum

{m}_{1	}{v }_{1} \\

 = ({m}_{1} +{m }_{2} ){v}-{2}→{v}_{2} \\

= \frac{{m}_{1}}{{m}_{1} +{m}_{2}}×{ v }_{1}

The ratio of kinetic energies before & after collision is

\frac{{KE}_{f}}{{KE}_{i}} \\

= \frac{\frac{1}{2}×({m}_{1}+{m}_{2}) × (\frac{{m}_{1}}{{m}_{1} +{m}_{2}}×{ v }_{1})²}{\frac{1}{2}×{m}_{1}{v²}_{1}} \\

 = \frac{{m}_{1}}{{m}_{1} +{m}_{2}}{×}{ v }_{1}

The fraction of kinetic energy lost is

\frac{{KE}_{i} – {KE}_{f}}{{KE}_{i}} \\

 = \frac{1 –( \frac{{m}_{1}}{{m}_{1} +{m}_{2}})×{ v }_{1}}{{KE}_{i}} × {KE}_{i} \\

 = \frac{{m}_{2}}{{m}_{1} +{m}_{2}}×{ v }_{1}

Hence energy always loss in inelastic collision.

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