show that there is no positive integer n for which √n-1 +√n+1 is rational
Answers
Answered by
3
Suppose that sqrt(n-1) + sqrt(n+1) is rational.
Then its square [sqrt(n-1) + sqrt(n+1)]^2 = 2n + 2 * sqrt(n^2 -1) is also rational.
Next, since 2 and n are rational, by the closure laws of Q, we have that
sqrt(n^2 - 1) is rational. This proof will be complete if we can prove the following fact.
Claim: sqrt(n^2 - 1) is irrational.
This follows from the claim that consecutive squares are spaced more than 1 unit apart as long as n^2 > 1. [(n+1)^2 - n^2 = 2n + 1.]
More precisely, since (n - 1)^2 < n^2 - 1< n^2 for all integers n > 1, taking square roots shows that sqrt(n^2 - 1) is between two consecutive perfect squares.
Hope it helps you
Then its square [sqrt(n-1) + sqrt(n+1)]^2 = 2n + 2 * sqrt(n^2 -1) is also rational.
Next, since 2 and n are rational, by the closure laws of Q, we have that
sqrt(n^2 - 1) is rational. This proof will be complete if we can prove the following fact.
Claim: sqrt(n^2 - 1) is irrational.
This follows from the claim that consecutive squares are spaced more than 1 unit apart as long as n^2 > 1. [(n+1)^2 - n^2 = 2n + 1.]
More precisely, since (n - 1)^2 < n^2 - 1< n^2 for all integers n > 1, taking square roots shows that sqrt(n^2 - 1) is between two consecutive perfect squares.
Hope it helps you
Answered by
1
Answer:
follow this link for answer
https://brainly.in/question/2431758
Similar questions