show that there is no rational number whose square is 3.
Answers
Step-by-step explanation:
if √3 is irrational then there exists no rational number with square 3
to prove :√3 is irrational
proof:Let us assume to the contrary that √3 is a rational number.
It can be expressed in the form of p/q
where p and q are co-primes and q≠ 0.
⇒ √3 = p/q
⇒ 3 = p2/q2 (Squaring on both the sides)
⇒ 3q2 = p2………………………………..(1)
It means that 3 divides p2 and also 3 divides p because each factor should appear two times for the square to exist.
So we have p = 3r
where r is some integer.
⇒ p2 = 9r2………………………………..(2)
from equation (1) and (2)
⇒ 3q2 = 9r2
⇒ q2 = 3r2
Where q2 is multiply of 3 and also q is multiple of 3.
Then p, q have a common factor of 3. This runs contrary to their being co-primes. Consequently, p / q is not a rational number. This demonstrates that √3 is an irrational number.
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SOLUTION
TO PROVE
There is no rational number whose square is 3.
EVALUATION
We have to show that there is no rational number whose square is 3.
If possible let there is a rational number x whose square is 3.
Then x² = 3
⇒ x = √3
Since x is a a rational number , then it should be in the form of p/q
where p and q are co- prime number.
So,
√3 = p/q { where p and q are co- prime}
⇒ √3q = p
Now, by squaring both the side
we get,
⇒ (√3q)² = p²
⇒ 3q² = p² - - - - - - - - (1)
So
If 3 is the factor of p²
then, 3 is also a factor of p - - - - - - - (2)
⇒ Let p = 3m { where m is any integer }
Squaring both sides
p² = (3m)²
⇒ p² = 9m²
putting the value of p² in Equation 1
3q² = p²
⇒ 3q² = 9m²
⇒ q² = 3m²
So,
if 3 is factor of q²
then, 3 is also factor of q
Since
3 is factor of p & q both
So, our assumption that p & q are co- prime is wrong
Therefore √3 is an irrational number
Hence there is no rational number whose square is 3.
Hence the proof follows
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