Show that these altitudes are equal.
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4.
ABC is a triangle in which altitudes BD and CE to sides AC
and AB are equal (see figure). Show that
(1) AABD = AACE
(1) AB = AC i.e., ABC
is an isosceles triangle.
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In right-angle triangles BCE and CBF, we have,
BC = BC (common hypotenuse);
BE = CF (given).
Hence BCF and CBF are congruent, by RHS theorem. Comparing the triangles, we get ∠B=∠C.
This implies that
AC = AB (sides opposite to equal angles).
Similarly,
AD=BE⇒∠B=∠A
⇒AC=BC
Together, we get AB=BC=ACor △ABC is equilateral. [henceproved]
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