Question

show that this question please answer fast iwill wait​

Answer 1

Answer:

Step-by-step explanation:

=(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)

=(a^2-b^2)+(b^2-c^2)+(c^2-a^2)

=(a^2-b^2+b^2-c^2+c^2-a^2

=0