Question

show that tn for the AP 13, 18, 23, 28,... is 5n + 8.​

Answer 1

$t_{n}$ = 8 + 5n , proved.

Step-by-step explanation:

The given AP are:

13, 18, 23, 28, ......

Here, first term(a) = 13, common difference(d) = 18 - 13 = 5

Show that $t_n$ for the AP 13, 18, 23, 28,... is 5n + 8.​

We know that,

The nth term of an A.P.,

$t_{n} =a+(n-1)d$

⇒ $t_{n}$ = 13 + (n - 1) 5

⇒ $t_{n}$ = 13 + 5n - 5

⇒ $t_{n}$ = (13 - 5) + 5n

⇒ $t_{n}$ = 8 + 5n  , proved.

Thus, $t_{n}$ = 8 + 5n , proved.

Answer 2

Step-by-step explanation:

hope it will be help u !!!!!