SHOW THAT TOTAL MECHANICAL ENERGY OF A FREE FALLING BODY REMAINS CONSERVED THROUGHOUT ITS FALL?
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Hey!
___________
Let us consider a body of mass m placed at A
h = AB = Height of body from ground
s = Distance if any point C from A
g = Acceleration due to gravity
v1 = Velocity of the body at C
v = Velocity of body at B
Velocity at point A = 0
____________
(i) Mechanical energy at Point A
Potential energy at A = E (pA) = mgh
Kinetic energy at A = E (kA) = 0
Total mechanical energy at A (Ea) = E (pa) + E (kA)
= mgh + 0 = mgh -------- (i)
____________
(ii) At point C
When body moves from A to C, it covers distance 's'. and v1 us velocity at C then from,
v^2 - u^2 = 2as
v1^2 - 0 = 2 gs
Kinetic energy at C = E (kC) = 1/2 mv^2
= 1/2 m (2gs)
= mgs
Potential energy at C = E (pC) = mg (h - s)
Total mechanical energy at C = E (C) =
E (C) = E (pC) + E (kC) = mg (h-s) + mgs = mgh ------ (ii)
____________
(iii) At point B
v2 = 2gh
Kinetic energy at B = E (kB) = 1/2 mv^2
= 1/2 m (2gh) = mgh
Potential energy at B = E (pB) = 0
Total mechanical energy = E (B) =
E (B) = E (kB) + E (pB) = mgh + 0 = mgh ----- (iii)
From (i) , (ii) and (iii)
E (A) = E (B) = E (C)
mgh = mgh = mgh
Total mechanical energy was same at all the three points. This proves that -
The total mechanical energy of the body throughout the free fall is conserved.
NOTE - We have neglected effect of AIR RESISTANCE on the motion of body.
___________
Hope it helps...!!!
___________
Let us consider a body of mass m placed at A
h = AB = Height of body from ground
s = Distance if any point C from A
g = Acceleration due to gravity
v1 = Velocity of the body at C
v = Velocity of body at B
Velocity at point A = 0
____________
(i) Mechanical energy at Point A
Potential energy at A = E (pA) = mgh
Kinetic energy at A = E (kA) = 0
Total mechanical energy at A (Ea) = E (pa) + E (kA)
= mgh + 0 = mgh -------- (i)
____________
(ii) At point C
When body moves from A to C, it covers distance 's'. and v1 us velocity at C then from,
v^2 - u^2 = 2as
v1^2 - 0 = 2 gs
Kinetic energy at C = E (kC) = 1/2 mv^2
= 1/2 m (2gs)
= mgs
Potential energy at C = E (pC) = mg (h - s)
Total mechanical energy at C = E (C) =
E (C) = E (pC) + E (kC) = mg (h-s) + mgs = mgh ------ (ii)
____________
(iii) At point B
v2 = 2gh
Kinetic energy at B = E (kB) = 1/2 mv^2
= 1/2 m (2gh) = mgh
Potential energy at B = E (pB) = 0
Total mechanical energy = E (B) =
E (B) = E (kB) + E (pB) = mgh + 0 = mgh ----- (iii)
From (i) , (ii) and (iii)
E (A) = E (B) = E (C)
mgh = mgh = mgh
Total mechanical energy was same at all the three points. This proves that -
The total mechanical energy of the body throughout the free fall is conserved.
NOTE - We have neglected effect of AIR RESISTANCE on the motion of body.
___________
Hope it helps...!!!
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Answered by
26
Hey there
Let's explore something new before proofing this statement , Why I'm telling you ? It is because the theories I will discuss which will be use over here so it will be better to you to understand it First .
• What is mechanical Energy ?
→ Mechanical energy is the sum of the kinetic and potential Energy
Thus if M is the machanical energy then it can be written as
→ M = KE + PE ..... ( 1 )
• What do you mean by the Conservation of energy ?
→ This statement states that , Energy can neither be created nor be destroyed but it can be transferred from one form to another
For example :-
• Have you ever heard about photosynthesis ? this is a real life example of the energy conversion , light energy is converted to Chemical energy
•What did you eat today ? You know what the food that you eat is digested and give energies to you by the process respiration
well we have learnt so much thing yet
Now let's proof this statement
Suppose you are climbing up to Mount everest how good it is xD ,
then we know a body have mass , this body is affected by the gravity , and the body goes to the height , due to change in the position up it produces velocity
these are can be denoted as
Velocity , = V
Mass , = m
Gravity ,/ acceleration due to free fall = g
height , = h
[ see the attached picture no -1 ]
where
Kinetic energy , KE = 0 [ since no any motion at that time ]
Potential Energy = mgh
From equation [ 1 ]
Mechanical Energy = 0 + mgh= mgh
Suppose a body with m is falling from the hight ( h - x ) with velocity vB at point B it produces gravity g covered the distance x
then
•Potential Energy , PE = mg ( h - x )
By 3rd equation of motion:-
or
• kinetic energy
Where
PE =0
Velocity , Vc
and kinetic energy
so mechanical Energy = 0 + mgh = mgh
Thus at Different point the value mechanical energy is the same Hence it is proved that it is conserved at different points
Hope this helps you ☺
Let's explore something new before proofing this statement , Why I'm telling you ? It is because the theories I will discuss which will be use over here so it will be better to you to understand it First .
• What is mechanical Energy ?
→ Mechanical energy is the sum of the kinetic and potential Energy
Thus if M is the machanical energy then it can be written as
→ M = KE + PE ..... ( 1 )
• What do you mean by the Conservation of energy ?
→ This statement states that , Energy can neither be created nor be destroyed but it can be transferred from one form to another
For example :-
• Have you ever heard about photosynthesis ? this is a real life example of the energy conversion , light energy is converted to Chemical energy
•What did you eat today ? You know what the food that you eat is digested and give energies to you by the process respiration
well we have learnt so much thing yet
Now let's proof this statement
Suppose you are climbing up to Mount everest how good it is xD ,
then we know a body have mass , this body is affected by the gravity , and the body goes to the height , due to change in the position up it produces velocity
these are can be denoted as
Velocity , = V
Mass , = m
Gravity ,/ acceleration due to free fall = g
height , = h
[ see the attached picture no -1 ]
where
Kinetic energy , KE = 0 [ since no any motion at that time ]
Potential Energy = mgh
From equation [ 1 ]
Mechanical Energy = 0 + mgh= mgh
Suppose a body with m is falling from the hight ( h - x ) with velocity vB at point B it produces gravity g covered the distance x
then
•Potential Energy , PE = mg ( h - x )
By 3rd equation of motion:-
or
• kinetic energy
Where
PE =0
Velocity , Vc
and kinetic energy
so mechanical Energy = 0 + mgh = mgh
Thus at Different point the value mechanical energy is the same Hence it is proved that it is conserved at different points
Hope this helps you ☺
Attachments:
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