show that triangle ABD congruent to triangle ACD, hence prove that angle ADB = angle ADC=90°
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Step-by-step explanation:
In ABD and ACD
AB =AC (side)
BD =CD (side)
AD is common (side)
Therefore ABD Is congruent to ACD (SSS congruence)
By cpct,
Angle ADB =ANgleACD
But ABD+ACD=180degrees (linear pair)
From cpct ACD+ACD=180
2ACD=180
ACD = 90 degrees
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