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Trigonometry question
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Step-by-step explanation:
sinA/secA+tanA-1+cosA/cosecA+cotA-1
=sinAcosA/1+sinA-cosA +cosAsinA/1+cosA-sinA
=sinAcosA/1+(sinA-cosA)+sinAcosA/1-(sinA-cosA)
=[sinAcosA{1-(sinA-cosA)} +sinAcosA{1+(sinA-cosA)}]/1-(sinA-cosA)²
=sinAcosA{1-(sinA-cosA)+1+(sinA-cosA)}/1-(1-2sinAcosA)
=2sinAcosA/2sinAcosA
=1
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