show that two distinct lines cannot have more than one point in common
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Let l and m be two distinct lines .
If possible , let P and Q be two points common to l and m . Then l contains both points P and Q . And , m also contains both the points P and Q . But , there is only one line passing through two distinct points .
Therefore, l = m
This indicates the hypothesis that l and m are distinct .
Thus , our supposition is wrong .
Hence , two distinct lines cannot have more than one point in common .
Hope ....it will be helpful for you ...!!!
If possible , let P and Q be two points common to l and m . Then l contains both points P and Q . And , m also contains both the points P and Q . But , there is only one line passing through two distinct points .
Therefore, l = m
This indicates the hypothesis that l and m are distinct .
Thus , our supposition is wrong .
Hence , two distinct lines cannot have more than one point in common .
Hope ....it will be helpful for you ...!!!
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