Show that u= 12 log(x2+y2) is Harmonic and find its Harmonic conjugate function
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Answer: What you got in the first step is correct. That is, when we integrate
∂v∂y=xx2+y2=1x1+(yx)2=∂∂y(yx)1+(yx)2=∂∂y(tan−1(yx)),
we obtain v=tan−1(yx). Note that in your second step:
∂v∂x=−yx2+y2=−yx21+(yx)2=∂∂x(yx)1+(yx)2=∂∂x(tan−1(yx)).
Integrate it, again we get v=tan−1(yx).
Explanation:
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