Question

show that under root 2 is irrational no.(by the method of contradiction). Also explain the method of contradiction deeply​

Answer 1

Step-by-step explanation:

let

√2 is rational number

=> √2 = a/b and a, b have no common factor

=> 2= a²/b²

=> b²= a²/2 => a=2k (even)

=> b² = 2k² (even)

=> a and b both are even but our assumption

that a and b has no common factor

=> contradict our assumption

=> √2 is an irrational number.