show that value of 'g ' doesnot depend upon mass of object
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The acceleration due to gravity neverdepends on the mass.
The acceleration of mass m due to mass M is given by:
F=GMm/r² =ma
⟹a=GM/r²
F=GMm/r² =ma
⟹a=GM/r²
see, does not depend on m
(does depend on M though .... that is, it depends on the other mass!)
This makes sense, after all: all macroscopic objects are made from an assortment of bits of different masses.
If different masses fell at different rates, then the object will have to decide which mass to use to dictate it’s overall rate of falling.
The acceleration of mass m due to mass M is given by:
F=GMm/r² =ma
⟹a=GM/r²
F=GMm/r² =ma
⟹a=GM/r²
see, does not depend on m
(does depend on M though .... that is, it depends on the other mass!)
This makes sense, after all: all macroscopic objects are made from an assortment of bits of different masses.
If different masses fell at different rates, then the object will have to decide which mass to use to dictate it’s overall rate of falling.
muddassirnawazkhan:
Please check if the answer I gave was correct.
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We know that the value of g is 9.8m/s^2. To get the value of g we use this equation G*M/R^2 where G is the universal gravitational constant= 6.673*10^-11 Nm^2 kg^-2, M is the mass of the earth= 6*10^24 kg and R is the radius of the earth= 6.4*10^6 m. We also know that the value of g changes with the radius of the earth, because the value of g on the poles is greater when compared to the equator.
So now we can come to the conclusion that. the value of g depends on the mass of the object which attracts the other object towards it and not the object which is being attracted.
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I hope your doubt was clarified.
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