Question

Show that vectors a=2i+3j+6k
b=3i-6j+2k and c=6i+2j-3k are
mutually perpendicular.​

Answer 1

Answer:

Since vectors are perpendicular.

so,abc=(2i+3j+6k)(3i-6j+2k)(6i+2j-3k)

abc=36×1-36×1-36×1

abc=-36.

hope it'll help you..