Question

Show that vectors a=2i+3j+6k,b=3i-6j+2k and c= 6i+2j-3k are mutually perpendiular

Answer 1

Explanation:

For 2 vectors to be perpendicular their dot product ( scalar product ) should be equal to zero ( 0 )

So a•b = 0

→ (2i + 3j + 6k )(3i-6j+2k)

→ 6 - 18 + 12

→ 0

Similarly as the vectors are mutually perpendicular So :

b•c = 0

→ ( 3i-6j+2k ) ( 6i + 2j - 3k )

→ 18 - 12 - 6

→ 0

and a•c is also equal to zero

Hence , the vectors a , b and c are mutually perpendicular