Question

show that weber=volt.second

Answer 1

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The SI unit for weber is (m^2 x kg)/(s^2 x A).
One volt equals to one joule/coulomb,
which is : W/Q.
Now, the SI unit for volt is (m^2 x kg)/(s^3 x A). 
now volt x sec = (m^2 x kg x s)/(s^3 x A)
volt x sec = (m^2 x kg)/(s^2 x A)
volt x sec​ =  weber 
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Answer 2

Given :

The equation Weber = volt.second

To Find :

To prove Weber = volt.second

Solution :

According to Faraday's Second Law, The strength of the induced emf is directly proportional to the time rate of change of magnetic flux linked with the coil.

If the change in magnetic flux linked with a coil in time dt be d$\alpha$ , according to Faraday's second law,

                 Induced EMF (E) = $\frac{d\alpha }{dt}$

The unit for magnetic flux is Weber, EMF is volt and time is Second.

So,               Volt        =     $\frac{Weber}{Second}$

∴               Weber      =   Volt.Second  (Proved)