show that when a number is multiplied by 6, then 8 is added to it, then sum is divided by two and twice the original number is subtracted from it, then number is equal to the original number
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Answer: x+4
Step-by-step explanation:
Let "x" be the number.
1. If a number is multiplied by 6,
(x)(6) or simply 6x,
2. then add 8,
6x+8
3. Divided by 2,
(6x+8)/2
4. and twice the original number (x) is subtracted from it
(6x+8)/2 - 2x
to simplify,
3x+4-2x = x+4
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Answer:
Step-by-step explanation:
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