Question

show that (x-1)^2 is a factor of x^n-nx+n-1​

Answer 1

Step-by-step explanation:

nx+9=(n+1)×(x+1)

nx+9=nx+x+n+1

nx+x+n+1-nx-9=0

x+n-8=0

x+n=8

From 2:-

nx-11=(n-1)(x-2)

nx-11=nx-x-2n+2

nx-11-nx+x+2n-2=0

x+2n-13=0

x+2n=13

By Taking Both Equations

x+n=8

x+2n=13

_____________

-n=-5

so,n=5

By Putting the Value of 'n' in Equation no.1

x+n=8

x+5=8

x=8-5

x=3

So,Value Of

x=3

n=5

Answer 2

Answer:

n=5

Step-by-step explanation:

nx+9=(n+1)×(x+1)

nx+9=nx+x+n+1

nx+x+n+1-nx-9=0

x+n-8=0

x+n=8

From 2:-

nx-11=(n-1)(x-2)

nx-11=nx-x-2n+2

nx-11-nx+x+2n-2=0

x+2n-13=0

x+2n=13

By Taking Both Equations

x+n=8

x+2n=13

_____________

-n=-5

so,n=5

By Putting the Value of 'n' in Equation no.1

x+n=8

x+5=8

x=8-5

x=3

So,Value Of

x=3

n=5