Question

show that ( x ^ 1 / a -b )^1a-c.(x^1/b-c^)^1/b-a(x^1/c-a)^1/c-b=1 where a is not equal to b is not equal to c .​

Answer 1

Step-by-step explanation:

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=(x)^1/(a-b)(a-c)* (x)^1/(b-c)(b-a)* (x)^1/(c-a)(c-b)

=(x)^1/(a-b)(a-c)+1/(b-c)(b-a)+1/(c-a)(c-b)

=(x)^1/(a-b)(a-c)+1/(b-c)+(1/(b-a)-1/(c-a))

=x^1/(a-b)(a-c)+1/(b-c) (c-a+a-b/(b-a)(c-a))

=x^1/(a-b)(a-c)+1/(c-b)/(b-c)(b-a)(c-a)

=x^1/(a-b)(a-c)+1/(b-a)(c-a)

=x^1/(a-b) (c-a+a-c/(c-a))

=0/x^a-b=1

Unless x=0

Hope it helps uh!!..

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