Show that X-1 and x+4 are the
Factor of the polynomials x3+x²-10X
+8
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Step-by-step explanation:
If x-1 is a factor of x^3+x^2-10x+8 then if we put 1 in place of x then value should be 0
Steps:-
putting x=1
=(1)^3+(1)^2-10(1)+8
=1+1-10+8
=10-10
=0
So we can conclude that x-1 is a factor .
If x+4 is a factor of x^3+x^2-10x+8 then if we put -4 in place of x then value should be 0
Steps:-
putting x=-4
=(-4)^3+(-4)^2-10(-4)+8
=-64+16+40+8
=-64+64
=0
So we can conclude that x+4 is a factor.
hope it helps
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