show that (x+1) is a factor of 4x*2+3x-1.
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If (x+1) is a factor of the given polynomial, the zero of the same factor should satisfy the value for the polynomial.
(x+1) =0
=> x = -1.
Now putting value of x in the given polynomial;
4x^2 +3x -1 =0
=> 4 (-1)^2 + 3 (-1) -1 =0
=> 4 -3 -1 =0
=> 4 -4 =0
=> 0=0.
So, (x+1) is a factor of the given Polynomial
HENCE PROVED
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