Question

show that (x-1) is a factor of 4x^3+3x^2-4x-3 by using factor theorem ​

Answer 1

Step-by-step explanation:

let g(x)=x-1

=x=1

put p(1)= 4(1)³+3(1²)-4(1)-3

= 4+3-4-3

= 7-7

=0

so x-1 is factor of p(x)

Answer 2

Step-by-step explanation:

f (1)= 4*1^3 + 3*1^2 - 4*1 - 3

=4+3-4-3

=0

since f(1) = 0

(x-1) is a factor of this