Show that (x-1) is a factor of a polynomial p(x) = x3 - 6x +5 and hence factorise p (x)
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Hey friend, Here is your answer-
X-1
x = 1
P (x) = x3 - 6x + 5
P (1) = 1^3 - 6×1 + 5
P (1) = 1 - 6 + 5
P (1) = 1 - 1
P (1) = 0
Therefore (x-1) is a factor of this polynomial.
Hope it will help you.
X-1
x = 1
P (x) = x3 - 6x + 5
P (1) = 1^3 - 6×1 + 5
P (1) = 1 - 6 + 5
P (1) = 1 - 1
P (1) = 0
Therefore (x-1) is a factor of this polynomial.
Hope it will help you.
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