Question

show that (x-1) is a factor of p(x) = 2x^3 - 3x^2+7x-6​

Answer 1

Step-by-step explanation:

to show (x-1) is a factor of p(x)

put the value of x in p(x) as 1

I.e, p(1)= 2×(1)^3-3×(1)^2+7×1-6

= 2-3+7-6

= -1+1

=0

Hence, (x-1) is a factor of p(x).