Question

show that (x-1) is a factor of x^10-1​

Answer 1

X-1

x=1

By substituting the value of x in the polynomials

i) x^10-1

=(1)^10 -1

= 1-1

=0

So by factor theorem ( x-1) is a factor of x^10 -1

ii) x^11 -1

= (1)^11-1

= 1-1

=0

As the remainder is 0 so, again by factor theorem ( x-1) is a factor of x^11 -1