Question

show that (x+1) is a factor of (x ^100-1) and also of (x^101-1)​

Answer 1

Answer:

Step-by-step explanation:f(p)=x^100-1

g(p)=x^101-1

It says to check (x+1) whether:

(x+1) is a factor of f & g function.

f(-1)=(-1)^100-1

      =1-1

      =0

g(-1)=(-1)^101-1

       =-1-1

       =-2

Therefore, (p+1) is a factor

Plz mark as brainlist