Math, asked by arshikaul, 1 year ago

show that x-1 is a factor of x^4-1 and also of x^12-1.

Answers

Answered by Panzer786
14
Hii friend,

X -1= 0

X = 1

P(X) = X⁴-1

P(1) = (1)⁴ -1 = 1 -1 = 0

Remainder came zero it means X-1 is a factor of X⁴-1.


(2) (X)^12 -1

P(X) = (X)^12 -1

P(1) = (1)^12 -1 = 1-1 = 0

Remainder came 0 in both the cases it means X-1 is a factor of X⁴-1 and aslo of X^12-1


HOPE IT WILL HELP YOU..... :-)

arshikaul: so u took it by remainder theorem yet i was not sure earlier but ya now i understood
arshikaul: thaaanks a lot
Answered by veronika1
6
Hello....☺

Here is your solution.....☺

Hope this helps you.....☺

Thanks...☺
Attachments:

arshikaul: thanks
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