show that x-1 is a factor of x^4-1 and also of x^12-1.
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Hii friend,
X -1= 0
X = 1
P(X) = X⁴-1
P(1) = (1)⁴ -1 = 1 -1 = 0
Remainder came zero it means X-1 is a factor of X⁴-1.
(2) (X)^12 -1
P(X) = (X)^12 -1
P(1) = (1)^12 -1 = 1-1 = 0
Remainder came 0 in both the cases it means X-1 is a factor of X⁴-1 and aslo of X^12-1
HOPE IT WILL HELP YOU..... :-)
X -1= 0
X = 1
P(X) = X⁴-1
P(1) = (1)⁴ -1 = 1 -1 = 0
Remainder came zero it means X-1 is a factor of X⁴-1.
(2) (X)^12 -1
P(X) = (X)^12 -1
P(1) = (1)^12 -1 = 1-1 = 0
Remainder came 0 in both the cases it means X-1 is a factor of X⁴-1 and aslo of X^12-1
HOPE IT WILL HELP YOU..... :-)
arshikaul:
so u took it by remainder theorem yet i was not sure earlier but ya now i understood
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