show that X + 1 is a factor of x cube + x square + X + 1
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Heya !!!
( X + 1 ) = 0
X = -1
P( X ) = X³ + X² + X + 1
P ( -1 ) = ( -1 )³ + ( -1 )² + ( -1 ) + 1
=> -1 + 1 - 1 + 1
=> 2 - 2
=> 0
Remainder = 0
So,
( X + 1 ) is a factor of the given polynomial.
★ HOPE IT WILL HELP YOU ★
( X + 1 ) = 0
X = -1
P( X ) = X³ + X² + X + 1
P ( -1 ) = ( -1 )³ + ( -1 )² + ( -1 ) + 1
=> -1 + 1 - 1 + 1
=> 2 - 2
=> 0
Remainder = 0
So,
( X + 1 ) is a factor of the given polynomial.
★ HOPE IT WILL HELP YOU ★
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1
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