show that [x-1] is a factor of x to the power -1 for a [y-1] [ y-1]
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Answered by
1
Answer:
Let p(x)=x
10
−1 and q(x)=x
11
−1
If (x−1) is factor of x
10
−1 and x
11
−1 then the value of p(x)=x
10
−1 and q(x)=x
11
−1 is zero when x−1=0 or x=1
Replace x by 1 we get
p(x)=x
10
−1
p(1)=(1)
10
−1
p(1)=1−1=0
And
q(x)=x
11
−1
q(1)=(1)
11
−1
q(1)=1−1=0
So p(1) and q(1) are zero
then x−1 is a factor of x
10
−1 and x
11
−1. pls follow and mark me brainlist and thanks
Answered by
0
Answer:
Let p(x)=x10−1 and q(x)=x11−1
If (x−1) is factor of x10−1 and x11−1 then the value of p(x)=x10−1 and q(x)=x11−1 is zero when x−1=0 or x=1
Replace x by 1 we get
p(x)=x10−1
p(1)=(1)10−1
p(1)=1−1=0
And
q(x)=x11−1
q(1)=(1)11−1
q(1)=1−1=0
So p(1) and q(1) are zero
then x−1 is a factor of x10−1 and x11−1
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