Question

show that x-1 is a factor of x¹⁰-1and also of x¹¹-1​

Answer 1

Answer:

Step-by-step explanation:

P(x) = x^10 - 1

By Remainder theoram

On putting x = 1, we get

P(1) = (1)^10 - 1

P(1) = 1 - 1

P(1) = 0

Remainder = 0

Hence, (x-1) is a factor of given polynomial...