show that(x-1)is a factor of (x10-1)
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Answered by
25
P(x) = x^10 - 1
By Remainder theoram
On putting x = 1, we get
P(1) = (1)^10 - 1
P(1) = 1 - 1
P(1) = 0
Remainder = 0
Hence, (x-1) is a factor of given polynomial...
By Remainder theoram
On putting x = 1, we get
P(1) = (1)^10 - 1
P(1) = 1 - 1
P(1) = 0
Remainder = 0
Hence, (x-1) is a factor of given polynomial...
Answered by
5
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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