show that (x-1) is a factor of x10 -1 and also of x11 -1
Answers
Answered by
123
x-1
x=1
By substituting the value of x in the polynomials
i) x^10-1
=(1)^10 -1
= 1-1
=0
So by factor theorem ( x-1) is a factor of x^10 -1
ii) x^11 -1
= (1)^11-1
= 1-1
=0
As the remainder is 0 so, again by factor theorem ( x-1) is a factor of x^11 -1
x=1
By substituting the value of x in the polynomials
i) x^10-1
=(1)^10 -1
= 1-1
=0
So by factor theorem ( x-1) is a factor of x^10 -1
ii) x^11 -1
= (1)^11-1
= 1-1
=0
As the remainder is 0 so, again by factor theorem ( x-1) is a factor of x^11 -1
Answered by
51
x=1
1. x10-1
(1)10-1
1-1
=0
2. x11-1
(1)11-1
1-1
=0
1. x10-1
(1)10-1
1-1
=0
2. x11-1
(1)11-1
1-1
=0
alphanso:
please do mark it as brainliest ;)
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