Show that (x-1) is a factor of x³-5x²-x+5.Hence, factorise x³-5x²-x+5.
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1.let p(x)= x³-5x²-x+5
q(x)=(x-1)
let q(x)=0
so x-1=0,x=1
putting the value of x in the polynomial
p(1)=1³-5×1²-1+5=0
so x-1 is a factor of the polynomial
2. x³-5x²-x+5=(x-1)(x²-4x-5)
(x-1)(x²-5x+4x-5)=(x-1)(x-5)(x+1)
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Refer to attached file for answer.
Hope this answer helps you ^_^ !
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