Question

show that x-1 is a factor x²-2x+1 by long division method​

Answer 1

Answer:

ans. is 0

for finding the remainder we need to use remainder theorom

let p(x)=x2+2x+1

Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).

−x+1=0

∴x=−1

p(−1)=(−1)2+2(−1)+1=0

Hence, remainder=0

Answer 2

Answer:

$x {}^{2} - 2x + 1$

$=( x - 1) {}^{2}$

$x = 1$

Thus (x-1 ) is a factor of x square -2x+1.