Question

Show that x=1 is a root of the p(x)=2x cube- 3 x +7x +6

Answer 1

I hope the given polynomial is :- p(x) = 2x^3 - 3x +7x +6
If 1 is the zero of the polynomial p(x) then:-
p(1) = 2(1)^3 -3(1) +7(1) + 6
p(1) = 2(1) - 3 + 7 +6
p(1) = 2-3+7+6 = 12
As p(1) is not equal to 0. Therefore, 1 is not the zero of polynomial p(x).

Answer 2

p(1)=2-3+7+6=12 so x=1 is not a root of the p(x)=2xcube-3x+7x+6