Show that x - 1 is a root of the polynomial 2 x³ - 3 x² + 7x - 6.
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Let-the polynomial f(x)=2x^3-3x^2+7x-6
and, g(x)=x-1
now, g(x)=o
x-1=0
x=1
now, putting x=1 in equation f(x) we get
let f(x)=0
f(1)=2×1³-3×1²+7×1-6=0
2-3+7-6=0
-1+1=0
0=0
hence this shows that x-1 is a root of f(x).
hope it helps.
thanks.
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