Show that X=1 is a root of the polynomial f(X) =x^3-6^3+11x-6
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f(X) =x^3-6^3+11x-6
put the value of x=1 in f(x)
if it is equal to 0 then it is the root of f(x)
1(1)^3-216+11(1)-6
=1-216+11-6
=-210
therefore it is not the root of f(x)
thank you
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