Question

Show that x = -1 is a tangent to circle
x2 + y2 – 2 = 0 at (-1, 1).​

Answer 1

Answer:

$x = -1 \\ x {}^{2} + {y}^{2} - 2 = 0 \\ {( - 1)}^{2} + y {}^{2} - 2 = 0 \\ ( - 1) \times ( - 1) + y \times y = 0 - 2 \\ + 1 + y {}^{2} = - 2 \\ y { }^{2} = - 2 - 1 \\ {y}^{2} = - 3$