Question

show that x+1 is factor of p(x) -4x^2+3x-1​

Answer 1

Answer:

Solution

• x + 1 = 0
• x = (-1)

If it's (-4) in front :-

p (x) = (-4x²) + 3x - 1

• [-4(-1)²] + 3(-1) - 1
• (-4) - 3 - 1
• (-8)

No it's not a factor of p(x)

If it's +4 in front

p (x) = (4x²) + 3x - 1

• [4(-1)²] + 3(-1) - 1
• (4) - 3 - 1
• 0

Yes x + 1 is a factor of p(x)