Question

Show that (x+1) is factor of p(x)= 4x2+3x-1

Answer 1

put x+1=0
we get x=-1
put x=-1 in p(x), we get P(1)= 0 . this is the remainder. if remainder is 0, it means(x+1) is a factor.

Answer 2

HERE IS YOURS PROOF;

◆ If (x+1) is a factor of the given polynomial, the zero of the same factor should satisfy the value for the polynomial.

(x+1) =0

=> x = -1.


Now putting value of x in the given polynomial;

4x^2 +3x -1 =0

=> 4 (-1)^2 + 3 (-1) -1 =0

=> 4 -3 -1 =0

=> 4 -4 =0

=> 0=0.

◆ So, (x+1) is a factor of the given Polynomial ◆


HENCE PROVED.



HOPE IT HELPS