Show that (x-1) (x-2) is a factor of polynomial x - x² - 4x + 4. Also find zeros of the polynomial.
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Step-by-step explanation:
x-1= 0
x= 0+1
x= 1
put p(x)= 1
p(1)=1-1²-4(1)+4
p(1)= 1-1-4+4
p(1)= 0
Therefore, (x-1) is a factor of the polynomial x-x²-4x+4.
x-2=0
x=0+2
x= 2
Now, put p(x)= 2
p(2)=2-2²-4(2)+4
p(2)= 2-4-8+4
p(2)= -2-4
p(2)= -6
Therefore, (x-2) is not a factor of x-x²-4x+4.
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