Show that [x^-1 + y^-1]/[x+y]=(xy)^-1
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Answered by
1
Answer:
LHS=(1/x+1/y)/(x+y)
x+y/xy/x+y/1
1/xy
(xy)^-1
RHS=(xy)^-1
LHS=RHS
Hence proved
Step-by-step explanation:
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Answered by
4
Answer:
[x^-1 + y^-1]/[x+y]=(xy)^-1
» [1/x+1/y]/[x+y]= 1/xy
» [y/xy + x/xy] / [x+y] = 1/xy
» [y+x]/xy/[x+y] = 1/xy
» [y+x] / [x²y+xy²] = 1/xy
» [y+x] / (xy) [x+y] = 1/xy
» 1/xy = 1/xy
» (xy)-¹ = (xy) -¹
hence proved
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