show that x=1is zero of the polynimial 2x^3-3x^2+7x-6
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Answered by
1
Heya !!!
X = 1
P(X) = 2X³ - 3X² + 7X -6
P(1) = 2 × (1)³ - 3 × (1)² + 7 × 1 -6
=> 2 × 1 - 3 × 1 + 7 - 6
=> 2 - 3 + 7 -6
=> 9-9
=> 0
Remainder = 0
Hence,
1 is a zero of the given polynomial.
★ HOPE IT WILL HELP YOU ★
X = 1
P(X) = 2X³ - 3X² + 7X -6
P(1) = 2 × (1)³ - 3 × (1)² + 7 × 1 -6
=> 2 × 1 - 3 × 1 + 7 - 6
=> 2 - 3 + 7 -6
=> 9-9
=> 0
Remainder = 0
Hence,
1 is a zero of the given polynomial.
★ HOPE IT WILL HELP YOU ★
Answered by
0
If (1) is the root of the equation, so remainder must be 0
By Remainder theorem,
=> 2x^3 - 3x^2 + 7x - 6
=> 2(1)³ - 3(1)² + 7(1) - 6
=> 2(1) - 3(1) + 7(1) - 6
=> 2 - 3 + 7 - 6
=> -1 + 1
=> 0
As the remainder of the given equation is 0, 1 is the factor of given equation.
I hope this will help you
(-:
By Remainder theorem,
=> 2x^3 - 3x^2 + 7x - 6
=> 2(1)³ - 3(1)² + 7(1) - 6
=> 2(1) - 3(1) + 7(1) - 6
=> 2 - 3 + 7 - 6
=> -1 + 1
=> 0
As the remainder of the given equation is 0, 1 is the factor of given equation.
I hope this will help you
(-:
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