Show That x^2-1 is divisible by x-1 and find the other factor
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Answer:
x^2-1=(x-1)(x+1). so it's divisible by x-1 and other factor is x+1
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Answer:
x²-1 = x² - 1²
a² - b² = (a+b)(a-b)
=> x² - 1² = (x+1)(x-1)
Since (x-1) is a factor of x² - 1, it is completely divisible.
To recheck;
p(x) = x² - 1
p(1) = 1² - 1 [Remainder Theorem]
p(1) = 0 [Factor Theorem]
The other factor is (x+1)
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