Question

Show that x^2 +8x+20 has no zero

Answer 1

Heya !!!



X² + 8X + 20


Here,



A = Coefficient of X² = 1



B = Coefficient of X = 8


And,


C = Constant term = 20




Discriminant (D) = B² -4AC



=> (8)² - 4 × 1 × 20



=> 64 - 80


=> -16 < 0



Discriminant of the given equation is smaller than 0. So , the given equation has no real zeroes .



★ HOPE IT WILL HELP YOU ★

Answer 2

x^2 + 8x + 20

a = 1
b = 8
c = 20

Discriminant = b^2 - 4ac

=> 8^2 - 4(1)(20)

=> 64 - 80

=> -16

As -16<0
So, equation has no real roots

$.$

I hope this will help you

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