show that X - 2 and X + 3 are the factors of x^3-x^2- 10x + 24
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Q1)roots=2,-3
(2)^3 - 2^2 - 20 +24=8-4-20+24=8
(-3)^3 - (-3)^2 +30 +24=-27-9+30+24=18
They are not factors of the equation.
Q2)x^2 + 1/x^2=66
(x-1/x)^2=x^2 + 1/x^2 - 2
x- 1/x = rt64=8
(2)^3 - 2^2 - 20 +24=8-4-20+24=8
(-3)^3 - (-3)^2 +30 +24=-27-9+30+24=18
They are not factors of the equation.
Q2)x^2 + 1/x^2=66
(x-1/x)^2=x^2 + 1/x^2 - 2
x- 1/x = rt64=8
Ganny1:
ok
then plz solve it. I have several doubts.
solved
where
I'm not able to see it
under the first ans
thanks a lot Ganny
no prob
no prob
great
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