show that (x-2)is a factor of 2x^4 -6x^3x-2
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86 is the answer ok friend
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[tx]\mathbb\green{GIVEN}[/tex]
- Show that x-2 is a factor of 2x⁴-6x³+3x²+3x-2 is correct question
[tex]\mathbb\green{METHOD TO BE USED}[/tex]
- Use factor theorem or remainder theorem to get 0. According to factor or remainder theorem when p(x) is divided by f(x) then use x-2=0,x=2 to get remainder as 0
[tex]\mathbb\green{SOLUTION}[/tex]
- According to remainder theorem
f(x)=x-2 ,x=2
- Substitute 2 in value of x
p(x)=2x⁴-6x³+x-2
p(2)=2×2⁴-6×2³+3×2²+3×2-2
2×16-6×8+3×4+6-2
32-48+12+4
-16+16 =0
Hence proved ,,,,......
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