Question

Show that (x+2)is a factor of f(x)=x^2+4x^2+x-6

Answer 1

Answer:

x=-2

Step-by-step explanation:

$= > f(x) = x ^{2} + 4 {x}^{2} + x - 6 \\ = > f(x) = 5x {}^{2} + x - 6 \\ = > f( - 2) = 5( - 2) {}^{2} + ( - 2) - 6 \\ = > f( - 2 ) = 5(4) - 2 - 6 \\ = > f( - 2) = 20 - 8 \\ = > f( - 2) = 12$

HOPE THIS WILL HELP YOU DEAR

KINDLY MARK IT THE BRAINLIEST

Answer 2

Step-by-step explanation:

(x+2) is a factor of f(x) means -2 is a zero of f(x)

f(-2) = (-2)^2+4*(-2)^2+(-2)-6

= 4+16-2-6

= 12

This implies that (x+2) is not a factor of f(x)..

I hope u understood the concept....