show that (x+2) is a factor of f(x)=x^3+4x^2+x-6
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Answered by
3
x+2=0
x=-2
-8+16-8=0
0=0
just because solution comes to be 0,(x+2) is a factor of x^3+4x^2+x-6
x=-2
-8+16-8=0
0=0
just because solution comes to be 0,(x+2) is a factor of x^3+4x^2+x-6
Answered by
3
x + 2 = 0
x = -2
(-2)^3 + 4(-2)^2 + (-2) -6
-8 + 4 × 4 -2 -6
-16 + 16 = 0
Yes, this is the factor of this polynomial.
This is the solution of your question. I hope that it will help you
x = -2
(-2)^3 + 4(-2)^2 + (-2) -6
-8 + 4 × 4 -2 -6
-16 + 16 = 0
Yes, this is the factor of this polynomial.
This is the solution of your question. I hope that it will help you
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